Uploaded May 2020 | Updated September 2026, 2 weeks ago
When looking for a next way to experiment on the behaviour of Tesla impulses I thought of using a copper bar and see on different distances what the behaviour of the signal would be.
The problem I'm always confronted with is the fact that allthough the drawings of a node on a wire look really nice and understandable to be able and use that energy, when I calculate the distance needed for that puls it's always so massive that it's just not usable at low frequencies. So there has to be a factor that I don't know off at the moment.
Let's take an example:
If we use a signal of 318Khz and pulse width of 1.65µsec then the beginning and ending of a pulse on a single wire would need 299792458m/sec x 0.951 (velocity factor of electricity through a wire) x 0.00000165sec = 470meter
When I calculate reversly from 2m wire then I end up with 142Mhz.
Am I looking at it the wrong way or am I missing another velocity factor?
I also thought on the sharpness of the puls edges, they can have voltage difference between 2 points much shorter then the full length of the pulse, and after all, voltage difference = possible energy to use.
When looking for a next way to experiment on the behaviour of Tesla impulses I thought of using a copper bar and see on different distances what the behaviour of the signal would be.
The problem I'm always confronted with is the fact that allthough the drawings of a node on a wire look really nice and understandable to be able and use that energy, when I calculate the distance needed for that puls it's always so massive that it's just not usable at low frequencies. So there has to be a factor that I don't know off at the moment.
Let's take an example:
If we use a signal of 318Khz and pulse width of 1.65µsec then the beginning and ending of a pulse on a single wire would need 299792458m/sec x 0.951 (velocity factor of electricity through a wire) x 0.00000165sec = 470meter
When I calculate reversly from 2m wire then I end up with 142Mhz.
Am I looking at it the wrong way or am I missing another velocity factor?
I also thought on the sharpness of the puls edges, they can have voltage difference between 2 points much shorter then the full length of the pulse, and after all, voltage difference = possible energy to use.
