Halogen Chemistry: Synproportionation of Bromide + Bromate @colorfulchemistry2569
Halogen Chemistry: Synproportionation of Bromide + Bromate  @colorfulchemistry2569
Uploaded September 2016 | Updated September 2026, 1 week ago
Halogenides and Halogenates form under acid catalysis the elemental halogens.
This is called synproportionation, where the product is an oxidation state between the
two former ones. Here it is 0 from -1 and +5.

Reduction:
2 BrO3(-) + 12 H3O(+) + 10e(-) to Br2 + 18 H2O

Oxidation:
2 Br(-) to Br2 + 2e(-)

In this experiment an aqueous solution of Potassium Bromide and Potassium Bromate is prepared (before the video). Then a few milliliters of Sulphuric Acid (38%) are added.
The color rapidly changes to a yellow (diluted bromine-water).
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Halogen Chemistry: Synproportionation of Bromide + Bromate

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