Uploaded July 2010 | Updated September 2026, 13 minutes ago
This is the first of three videos that aim to completely debunk the flood myth with hard science and simple mathematics
All figures are obtained from Wikipedia, which while not being the best reference source available, is generally accurate for our purposes and is readily available for anyone to check my figures if they wish
The calculations mentioned in this video are as follows:
Height of Mt Everest above sea level
8,848 m = 8.848 km
Area of the surface of the earth
510,072,000 Km2
Volume of floodwaters required to cover the earth to a depth of the height of mount Everest
8.848 x 510,072,000 = 4,513,117,056 km3
If half of this flood water came from below the ground and half of this water came from a vapour canopy in the Earth's atmosphere then...
2,256,558,528 Km3 of water was in the vapour cloud
1 km3 = 1,000,000,000 m3
1 m3 is approximately equal to 1 tonne
Therefore the vapour cloud weighed...
2,256,558,528,000,000,000 tonnes
If the earth was a tropical paradise before the flood as we are told then it would be safe to assume that the air temperature was around 30'C and air at 30'C cannot hold more than 30g/m2 of water or the water will condense (100% humidity).
1tonne = 1,000kg = 1,000,000g
30g/m2 = 0.00003kg/m2
Therefore it can be asserted that the vapour cloud had a volume of:
75,218,617,600,000,000,000,000 m3
This is equal to
75,220,000,000,000 km3
The volume of the Planet Neptune is
62,540,000,000,000 km3
Therefore the volume of the vapour cloud is greater than the volume of Neptune which has a diameter of about 49,528km. The diameter of the cloud is actually over 52,000km
Pressure at sea level was calculated as follows:
If half of the water required to flood the earth was in the Earth's atmosphere as a vapour cloud then that is a quantity equivalent to 4,424m of overall flood water.
1m3 of water is roughly equivalent to 1 tonne
Therefore on any single 1m2 of the earth surface at sea level 4,424m3 of water would be exerting a downward pressure giving a pressure of 4,424tonnes per m2 which is equivalent to 426 atmospheres
If the Noah and all the animals were used to living under such high pressures they would have died as this pressure rapidly dropped over a period of 40 days to just one atmosphere.
In the second part of this series we will look in more detail at the implications of having a Neptune sized cloud of water vapour in the Earth's atmosphere would have on Noah and his animals
Please feel free to rate, comment and subscribe.
If you wish to argue any of the points made in this video I would love to hear from you
Another great video on the same subject that uses a slightly different and more acurate method of calculating the volume of flood water required:
youtube.com/watch?v=7QJ7yZ9L1po
The user's name is Bushonomics, check him out.
This is the first of three videos that aim to completely debunk the flood myth with hard science and simple mathematics
All figures are obtained from Wikipedia, which while not being the best reference source available, is generally accurate for our purposes and is readily available for anyone to check my figures if they wish
The calculations mentioned in this video are as follows:
Height of Mt Everest above sea level
8,848 m = 8.848 km
Area of the surface of the earth
510,072,000 Km2
Volume of floodwaters required to cover the earth to a depth of the height of mount Everest
8.848 x 510,072,000 = 4,513,117,056 km3
If half of this flood water came from below the ground and half of this water came from a vapour canopy in the Earth's atmosphere then...
2,256,558,528 Km3 of water was in the vapour cloud
1 km3 = 1,000,000,000 m3
1 m3 is approximately equal to 1 tonne
Therefore the vapour cloud weighed...
2,256,558,528,000,000,000 tonnes
If the earth was a tropical paradise before the flood as we are told then it would be safe to assume that the air temperature was around 30'C and air at 30'C cannot hold more than 30g/m2 of water or the water will condense (100% humidity).
1tonne = 1,000kg = 1,000,000g
30g/m2 = 0.00003kg/m2
Therefore it can be asserted that the vapour cloud had a volume of:
75,218,617,600,000,000,000,000 m3
This is equal to
75,220,000,000,000 km3
The volume of the Planet Neptune is
62,540,000,000,000 km3
Therefore the volume of the vapour cloud is greater than the volume of Neptune which has a diameter of about 49,528km. The diameter of the cloud is actually over 52,000km
Pressure at sea level was calculated as follows:
If half of the water required to flood the earth was in the Earth's atmosphere as a vapour cloud then that is a quantity equivalent to 4,424m of overall flood water.
1m3 of water is roughly equivalent to 1 tonne
Therefore on any single 1m2 of the earth surface at sea level 4,424m3 of water would be exerting a downward pressure giving a pressure of 4,424tonnes per m2 which is equivalent to 426 atmospheres
If the Noah and all the animals were used to living under such high pressures they would have died as this pressure rapidly dropped over a period of 40 days to just one atmosphere.
In the second part of this series we will look in more detail at the implications of having a Neptune sized cloud of water vapour in the Earth's atmosphere would have on Noah and his animals
Please feel free to rate, comment and subscribe.
If you wish to argue any of the points made in this video I would love to hear from you
Another great video on the same subject that uses a slightly different and more acurate method of calculating the volume of flood water required:
youtube.com/watch?v=7QJ7yZ9L1po
The user's name is Bushonomics, check him out.
