Predict the Products of the Reaction for Pb(NO3)2 + KI : Lead(II) nitrate + Potassium iodide @wbreslyn

Uploaded February 2024 | Updated September 2026, 2 weeks ago

To predict the products of the chemical reaction between Pb(NO3)2 and KI (Lead(II) nitrate and Potassium iodide), we first need to recognize the type of reaction that will take place.

Because Pb(NO3)2 is a soluble salt and KI is also soluble, they will both dissociate into their respective ions in solution. Therefore, when they react, they will undergo a double displacement reaction, also known as a metathesis reaction.

The reaction between Pb(NO3)2 and KI will result in the formation of PbI2 , which is insoluble and will precipitate out of solution, and KNO3 (Potassium nitrate), which remains in solution. The balanced chemical equation for this reaction is:

Pb(NO3)2 (aq) + 2KI (aq) → PbI2 (s) + 2KNO3 (aq)

This reaction is an example of a precipitation reaction, where an insoluble solid forms from the reaction of soluble reactants. The Lead(II) iodide formed will appear as a yellow precipitate.

Predict the Products of the Reaction for Pb(NO3)2 + KI : Lead(II) nitrate + Potassium iodide

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