Palladium Chemistry: [Pd(Cl4](2-) (Pd in HCl/H2O2) @colorfulchemistry2569
Palladium Chemistry: [Pd(Cl4](2-) (Pd in HCl/H2O2)  @colorfulchemistry2569
Uploaded May 2017 | Updated September 2026, 1 week ago
Palladium is an interesting element. Being a Platinum-group metal and standing between Nickel and Platinum one might expect it to be unreactive. Funnily this is not the case and some people even joke it could be more reactive than Nickel. Obviously, this might be a bit too much but the reactivity can be compared to the one of silver with one important difference: Palladium usually does not build up many passive layers. Meaning that it can dissolve in HCl for example.

In this video, however, we cheated a little and this is first to make it shorter and second to make it more visible. Usually, oxygen in HCl is enough to slowly dissolve Palladium but we used H2O2 instead of the oxygen here. Now you might say there is no big difference but there is. The redox reaction now changed to the one of an acidified Peroxide which has a huge redox potential being capable of even dissolving gold and platinum to some extent!

And PdCl2 forms Pd(IV) in H2O2 as well!

Note however that we also tried it with HCl and Oxygen and a lot of boiling and it turned yellow as well!

What forms here is the complex [PdCl4](2-). While Nickel(II) already shows some square planar geometry, especially when working with cyano-Ligands for Palladium almost all complexes are square planar.

Also the coordination number of 4 is really common in Palladium chemistry. So if you have to guess, a square planar geometry is always a good guess when dealing with Pd(II). Even the aqua-complex only has 4 Ligands.
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Palladium Chemistry: [Pd(Cl4](2-) (Pd in HCl/H2O2)

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