This Theorem Mogs the Quadratic Formula @WrathofMath
This Theorem Mogs the Quadratic Formula  @WrathofMath
Uploaded February 2026 | Updated September 2026, 2 weeks ago
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You might think the quadratic formula mogs Vieta's formulas. But today we'll take a deep dive into defending the average Vieta's formulas fan, and see that they might be even more elegant and dominant than the average quadratic formula enjoyer. We'll prove Vieta for quadratics, solve an AMC10A problem from 2003, and discuss elementary symmetric polynomials. #mathmemes #mathematics

Outro Song: youtube.com/shorts/qp8YRBNMKds
(Longer Version: youtube.com/watch?v=Pw9aWBlCxPc )

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SOURCES
reddit.com/r/mathmemes/comments/1pzamba/discriminant_on_top
https://davidaltizio.web.illinois.edu/Vietas%20Formulas.pdf
Funkhouser, H. Gray. β€œA Short Account of the History of Symmetric Functions of Roots of Equations.” The American Mathematical Monthly, vol. 37, no. 7, 1930, pp. 357–65.

0:00 Intro
0:56 Quadratics and D
4:47 Vieta's Formulas
6:11 Proof
8:57 Finding the Vertex
10:42 Competition Problem
12:14 The Vieta Approximation
15:31 Beginnings
17:24 Symmetric Polynomials
19:56 Conclusion
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This Theorem Mogs the Quadratic Formula

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