Uploaded March 2026 | Updated September 2026, 3 weeks ago
Question no.3.14- The earth's surface has a negative surface charge density of 10^-9 C m^-2. The potential difference of 400 kV between the top of the atmosphere and the surface results (due to the low conductivity of the lower atmosphere) in a current of only 1800 A over the entire globe. If there were no mechanism of sustaining atmospheric electric field, how much time (roughly) would be required to neutralize the earth's surface? (This never happens in practice because there is a mechanism to replenish electric charges, namely the continual thunderstorms and lightning in different parts of the globe). (Radius of earth =6.37 10^6m.
| class 12 Physics old ncert solution by ujwal Kumar physics master | physics master academy is best coaching for all physics students. | ujwal kumar
best physics teacher of neet, JEE-Mains in delhi
Download our app for android and ios on-app.in/app/home?orgCode=vdtxq
Question no.3.14- The earth's surface has a negative surface charge density of 10^-9 C m^-2. The potential difference of 400 kV between the top of the atmosphere and the surface results (due to the low conductivity of the lower atmosphere) in a current of only 1800 A over the entire globe. If there were no mechanism of sustaining atmospheric electric field, how much time (roughly) would be required to neutralize the earth's surface? (This never happens in practice because there is a mechanism to replenish electric charges, namely the continual thunderstorms and lightning in different parts of the globe). (Radius of earth =6.37 10^6m.
| class 12 Physics old ncert solution by ujwal Kumar physics master | physics master academy is best coaching for all physics students. | ujwal kumar
best physics teacher of neet, JEE-Mains in delhi
Download our app for android and ios on-app.in/app/home?orgCode=vdtxq










