Uploaded September 2024 | Updated September 2026, 2 weeks ago
We are making history again by presenting a new visual proof of the 2000+ years old Ptolemy's theorem and Ptolemy's inequality.
00:00 Introduction
04:27 Geometry 101
08:19 Applications
14:46 Ptolemy's inequality
18:34 LIES
25:35 Animated proofs
28:57 Thank you!
30:53 Degenerate Easter Egg
There are some other proofs of Ptolemy's theorem/inequality based on scaling and aligning suitable triangles. However, none of them is as slick, beautiful and powerful as Rainer's new proof. In particular, check out the animated scaling proof on the wiki page for Ptolemy's theorem (and this youtu.be/ZK08Z5A9xH4) and check out the scaling proof by Claudi Asina and Roger Nelson: Proof Without Words: Ptolemy’s Inequality in Mathematics Magazine 87, (2014), p. 291. jstor.org/stable/10.4169/math.mag.87.4.291
Rainer was inspired by a classic scaling based proof of Pythagoras theorem that I presented here youtu.be/p-0SOWbzUYI?si=GeGzZ0R_Dj1AsXqR&t=371
You can find a couple of full text versions of the Almagest here
wilbourhall.org/index.html#ptolemy
classicalliberalarts.com/resources/PTOLEMY_ALMAGEST_ENGLISH.pdf
For more background info check out the very comprehensive wiki pages on:
Ptolemy’s theorem
en.wikipedia.org/wiki/Ptolemy%27s_theorem
Ptolemy’s inequality
en.wikipedia.org/wiki/Ptolemy%27s_inequality
Claudius Ptolemy
en.wikipedia.org/wiki/Ptolemy
The Almagest
sco.wikipedia.org/wiki/Almagest
Trigonometric identities
en.wikipedia.org/wiki/List_of_trigonometric_identities
Cyclic quadrilateral
en.wikipedia.org/wiki/Cyclic_quadrilateral
The optic equation
en.wikipedia.org/wiki/Optic_equation
There are very interesting higher-dimensional versions of Ptolemy's theorem just like there are higher-dimensional versions of Pythagoras theorem. I did not get around to talking them today. Google ...
Highly recommended:
T. Brendan, How Ptolemy constructed trigonometry tables, The Mathematics Teacher 58 (1965), pp. 141-149 jstor.org/stable/27967990
Tom M. Apostol, Ptolemy's Inequality and the Chordal Metric, Mathematics Magazine 40 (1967), pp. 233-235 jstor.org/stable/2688275
demonstrations.wolfram.com/PtolemysTableOfChords an interactive exploration of Ptolemy's table of chords
Ptolemy's theorem made a guest appearance in the the previous Mathologer video on the golden ratio: youtu.be/cCXRUHUgvLI
Here is a nice trick to make Ptolemy counterparts of Pythagorean triples. Take any two sets of Pythagorean triples:
5² = 3² + 4², 13² = 12² + 5², and combine them like this:
65² = 13² × 5²= 13²(4² + 3²) = 52² + 39²= 5²(12² + 5²) = 60² + 25².
Now combining the two right angled triangles 52-39-65 and 25-60-65 along the common diagonal in any of four different ways gives a convex quadrilateral with all sides integers. Note that you automatically get 5 integer lengths and then Ptolemy's theorem guarantees that the remaining side is a fraction. Scaling up everything by the denominator of that fraction gives one of the special integer-everywhere quadrilaterals. See also Brahmagupta quadrilaterals.
Here is a nice application of Ptolemy's theorem to a International Maths Olympiad problem youtube.com/watch?v=NHjtHOE1lks
In a cyclic quadrilateral the ratio of the diagonals equals the ratio of the sums of products of the sides that share the diagonals' end points: geogebra.org/m/XQr5jJQg This extension of Ptolemy's theorem is part of the thumbnail for this video.
T-shirt: cowsine :)
Music: Floating branch by Muted and I promise by Ian Post.
Enjoy,
burkard
We are making history again by presenting a new visual proof of the 2000+ years old Ptolemy's theorem and Ptolemy's inequality.
00:00 Introduction
04:27 Geometry 101
08:19 Applications
14:46 Ptolemy's inequality
18:34 LIES
25:35 Animated proofs
28:57 Thank you!
30:53 Degenerate Easter Egg
There are some other proofs of Ptolemy's theorem/inequality based on scaling and aligning suitable triangles. However, none of them is as slick, beautiful and powerful as Rainer's new proof. In particular, check out the animated scaling proof on the wiki page for Ptolemy's theorem (and this youtu.be/ZK08Z5A9xH4) and check out the scaling proof by Claudi Asina and Roger Nelson: Proof Without Words: Ptolemy’s Inequality in Mathematics Magazine 87, (2014), p. 291. jstor.org/stable/10.4169/math.mag.87.4.291
Rainer was inspired by a classic scaling based proof of Pythagoras theorem that I presented here youtu.be/p-0SOWbzUYI?si=GeGzZ0R_Dj1AsXqR&t=371
You can find a couple of full text versions of the Almagest here
wilbourhall.org/index.html#ptolemy
classicalliberalarts.com/resources/PTOLEMY_ALMAGEST_ENGLISH.pdf
For more background info check out the very comprehensive wiki pages on:
Ptolemy’s theorem
en.wikipedia.org/wiki/Ptolemy%27s_theorem
Ptolemy’s inequality
en.wikipedia.org/wiki/Ptolemy%27s_inequality
Claudius Ptolemy
en.wikipedia.org/wiki/Ptolemy
The Almagest
sco.wikipedia.org/wiki/Almagest
Trigonometric identities
en.wikipedia.org/wiki/List_of_trigonometric_identities
Cyclic quadrilateral
en.wikipedia.org/wiki/Cyclic_quadrilateral
The optic equation
en.wikipedia.org/wiki/Optic_equation
There are very interesting higher-dimensional versions of Ptolemy's theorem just like there are higher-dimensional versions of Pythagoras theorem. I did not get around to talking them today. Google ...
Highly recommended:
T. Brendan, How Ptolemy constructed trigonometry tables, The Mathematics Teacher 58 (1965), pp. 141-149 jstor.org/stable/27967990
Tom M. Apostol, Ptolemy's Inequality and the Chordal Metric, Mathematics Magazine 40 (1967), pp. 233-235 jstor.org/stable/2688275
demonstrations.wolfram.com/PtolemysTableOfChords an interactive exploration of Ptolemy's table of chords
Ptolemy's theorem made a guest appearance in the the previous Mathologer video on the golden ratio: youtu.be/cCXRUHUgvLI
Here is a nice trick to make Ptolemy counterparts of Pythagorean triples. Take any two sets of Pythagorean triples:
5² = 3² + 4², 13² = 12² + 5², and combine them like this:
65² = 13² × 5²= 13²(4² + 3²) = 52² + 39²= 5²(12² + 5²) = 60² + 25².
Now combining the two right angled triangles 52-39-65 and 25-60-65 along the common diagonal in any of four different ways gives a convex quadrilateral with all sides integers. Note that you automatically get 5 integer lengths and then Ptolemy's theorem guarantees that the remaining side is a fraction. Scaling up everything by the denominator of that fraction gives one of the special integer-everywhere quadrilaterals. See also Brahmagupta quadrilaterals.
Here is a nice application of Ptolemy's theorem to a International Maths Olympiad problem youtube.com/watch?v=NHjtHOE1lks
In a cyclic quadrilateral the ratio of the diagonals equals the ratio of the sums of products of the sides that share the diagonals' end points: geogebra.org/m/XQr5jJQg This extension of Ptolemy's theorem is part of the thumbnail for this video.
T-shirt: cowsine :)
Music: Floating branch by Muted and I promise by Ian Post.
Enjoy,
burkard
![What does this prove? Some of the most gorgeous visual shrink proofs ever invented
Bit of a mystery Mathologer today with the title of the video not giving away much. Anyway it all starts with the quest for equilateral triangles in square grids and by the end of it we find ourselves once more in the realms of irrationality. This video contains some extra gorgeous visual proofs that hardly anybody seems to know about.
0:00 Intro
0:47 First puzzle
2:24 Second puzzle
3:50 Edward Lucas
4:41 Equilateral triangles
13:15 3d & 3rd puzzle
19:52 30 45 60
29:31 Credits
Here are links to/references of some of the things I mention in the video:
Joel Hamkins blog posts that inspired this video:
http://jdh.hamkins.org/no-regular-polygons-in-the-integer-lattice/
http://jdh.hamkins.org/no-regular-polygons-in-the-hexagonal-lattice/
There is also a whole chapter about all this and much more related maths in his new book
https://www.amazon.com/Proof-Mathematics-Joel-David-Hamkins/dp/0262539799
Here is another really good article which includes a nice characterisation of the triangles that can be found in square grids plus a very good survey of relevant results:
Michael J. Beeson, Triangles with Vertices on Lattice Points, The American Mathematical Monthly 99 (1992), 243-252, https://www.jstor.org/stable/2325060?seq=1
Scherrers and Hadwingers articles:
Scherrer, Willy, Die Einlagerung eines regulären Vielecks in ein Gitter, Elemente der Mathematik 1 (1946), 97-98.
https://tinyurl.com/y45p64t7
https://gdz.sub.uni-goettingen.de/id/PPN378850199_0001?tify={%22pages%22:[101]}
Hadwiger, Hugo Über die rationalen Hauptwinkel der Goniometrie, Elemente der Mathematik 1 (1946), 98-100.
https://tinyurl.com/yx98kkqt
https://gdz.sub.uni-goettingen.de/id/PPN378850199_0001?tify={%22pages%22:[102],%22view%22:%22info%22}
Another, nice paper on rational (and algebraic) cosines
https://arxiv.org/pdf/1006.2938.pdf
Here is a solution to the first puzzle (one way to find the general formula):
https://nrich.maths.org/657/solution
The music in this video is by Chris Haugen, Fresh Fallen Snow (playing in the video) and Morning Mandolin (for the credits)
A couple of remarks:
1. Probably the simplest way to deduce the sin and tan parts of the rational trig ratio theorem is to realise that they follow from the cos part via the trigonometric identities: sin(x)=cos(90-x) and tan^2(x) = (1-cos(2x))/(1+cos(2x)). Note that the second identity implies that if tan(x) is rational, then cos(2x) is rational (if tan(x)=c/d, then tan^2(x)=c^2/d^2=C/D and cos(2x)=(D-C)/(D+C)).
2. Bug report.
a) Here I redefine cos(120◦) = 1.
https://youtu.be/sDfzCIWpS7Q?t=1362
Remarkable :(
b) This transition to the good stuff I clearly did not think through properly.
https://youtu.be/sDfzCIWpS7Q?t=1018
Its possible to make this work for all regular n-gons. There is only one complication that occurs for ns that are of the form 2 * odd. For the corresponding regular n-gons, if you pick up the edges in the order that they appear around the n-gon and assemble them into a star, things close up into (n/2)-stars. For all other n, things work exactly as I showed in the video. Having said that you can also assemble the edges of one of the exceptions into stars. Have a look at this https://imgur.com/68A3fEe and youll get the idea. Anyway lots more nice side puzzles to be explored here if you are interested :)
Enjoy!
Burkard
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14. Sep. 2021: Thank you very much Michael Didenko for your Russian subtitles. What does this prove? Some of the most gorgeous visual shrink proofs ever invented](https://i.ytimg.com/vi/sDfzCIWpS7Q/mqdefault.jpg)









