Packs Maths Classics #25 : gcd(n^p-1,n^q-1)=n^(gcd(p,q))-1 @PackSciences

Packs Maths Classics #25 : gcd(n^p-1,n^q-1)=n^(gcd(p,q))-1 @PackSciences

Uploaded February 2018 | Updated September 2026, 3 hours ago

Packs Maths Classics #25 : gcd(n^p-1,n^q-1)=n^(gcd(p,q))-1

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Pack's Maths Classics #25 : gcd(n^p-1,n^q-1)=n^(gcd(p,q))-1

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