Uploaded November 2012 | Updated September 2026, 3 weeks ago
Applying Ampere's Law to a coaxial cable with its cylindrical symmetry yields 2*pi*r*B(r) =mu_0*I_enclosed. This animation shows the results for this application of Ampere's Law both in the interior and exterior regions of the cable.
Applying Ampere's Law to a coaxial cable with its cylindrical symmetry yields 2*pi*r*B(r) =mu_0*I_enclosed. This animation shows the results for this application of Ampere's Law both in the interior and exterior regions of the cable.










