Uploaded March 2026 | Updated September 2026, 1 week ago
I was trying to use integration by parts for the integral of 1/sqrt(x^2+16), but I ended up getting the answer for the integral of 1/(x^2+16)^(3/2) instead!
Integral of 1/sqrt(x^2+16) using trig sub vs hyperbolic sub: youtu.be/YfrcIwdOC0U
π Shop my math t-shirts & hoodies: π amzn.to/3qBeuw6
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#blackpenredpen #calculus
I was trying to use integration by parts for the integral of 1/sqrt(x^2+16), but I ended up getting the answer for the integral of 1/(x^2+16)^(3/2) instead!
Integral of 1/sqrt(x^2+16) using trig sub vs hyperbolic sub: youtu.be/YfrcIwdOC0U
π Shop my math t-shirts & hoodies: π amzn.to/3qBeuw6
π Support this channel and get more content patreon.com/blackpenredpen
#blackpenredpen #calculus










