In a car race, car A takes time t second less than car B and finishes the finishing point with a ve @PhysicsMasterAcademy

Uploaded June 2026 | Updated September 2026, 2 weeks ago

In a car race, car A takes time t second less than car B and finishes the finishing point with a velocity v more than that of the car B. Assuming that the cars start from the rest and the travel with constant acceleration a1 and a2 respectively show that v = t√a1a2.
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