If a+b+c=0, then prove that (b+c)^2/3bc + (c+a)^2/3ca + (a+b)^2/3ab = 1. Polynomials class 9. @AviJainClasses
If a+b+c=0, then prove that (b+c)^2/3bc + (c+a)^2/3ca + (a+b)^2/3ab = 1. Polynomials class 9. @AviJainClasses
Uploaded January 2020 | Updated September 2026, 2 weeks ago
If a+b+c=0, then prove that (b+c)^2/3bc + (c+a)^2/3ca + (a+b)^2/3ab = 1. Polynomials class 9. #polynomialsbyavisir
The students are requested to visit the following link as well to understand a very similar question :
If ab+bc+ca=0 , find the value of (1/a^2 - bc) + (1/b^2 - ac) + (1/c^2 - ab). Polynomials class 9.
youtu.be/PrtI9BzGVmM
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If a+b+c=0, then prove that (b+c)^2/3bc + (c+a)^2/3ca + (a+b)^2/3ab = 1. Polynomials class 9.

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