Uploaded July 2014 | Updated September 2026, 1 day ago

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First bench test for my diy heatpump, in side the blue container ther is 100 liters of water. With the following data i can calculate the COP of the heatpump.

DT = 20 degrees
Mass = 100 liters
C = 4180J
PW = 0,528 kWh of used electricity

Q = M * C * DT = 100 * 4180 * 20 = 8360000 joule
E = 3600000 * 0,528 = 1900800 joule
COP= 4,398

Overall a very impressive test run.