Combined Gas Law Practice Problem: Find New Temperature @wbreslyn

Uploaded September 2024 | Updated September 2026, 2 weeks ago

In this video, we'll work through another combined gas law problem, focusing on finding the final temperature of a gas when pressure and volume change. We'll emphasize the importance of ensuring units cancel out correctly during the calculation, a key step in solving gas law problems accurately.

Problem:

A gas initially at 2.00 atm, 1.20 L, and 273 K has its pressure reduced to 0.90 atm and the volume is increased to 3.1 L. Determine the final temperature.

We'll use the combined gas law to solve for the unknown final temperature, given the initial and final pressure and volume conditions.

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$Convert 6.0 L to mL (6 Liters to Milliliters) To convert 6 liters (L) to milliliters (mL), you can use the following steps. Note that the L will cancel out as you perform the conversion, leaving only mL: Conversion Factor: 1 liter (L) = 1000 milliliters (mL) Start with the quantity you want to convert (6 L) and set up a ratio where the original unit (L) is in the denominator and the target unit (mL) is in the numerator, using the conversion factor: Conversion factor: 1000 mL / 1 L Write the quantity you want to convert (6 L) as a fraction over 1: 6 L / 1 Multiply this fraction by the conversion factor: (6 L / 1) * (1000 mL / 1 L) Notice that the units of liters (L) in the numerator and denominator cancel out, leaving only the units of milliliters (mL): (6 * 1000) / (1 * 1) mL = 6000 / 1 mL = 6000 mL So, 6 L is equivalent to 6000 milliliters. The units of liters cancel out during the conversion process, leaving only milliliters as the final unit.$

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