Uploaded July 2018 | Updated September 2026, 1 week ago

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▼Open description▼

►This is the program I mentioned in the video:
var0 = 1
var1 = 1
var3 = 121
proj_num(var3 ,0 ,var0)
proj_num(var3 ,64 ,var1)
WHILE var1 〈 1500000000
var2 = var1
var1 = var1 + var 0
var0 = var2
var3 = var3 - 7
proj_num(var3 ,0 ,var1)
WEND
proj_num(var3 ,0 ,666)
render
END

It's not really useful for you, I guess. But now you know what a program for this computer will look like.


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