A Neat and Tidy Recursion Problem! @DrWeselcouch

Uploaded June 2021 | Updated September 2026, 22 minutes ago

See the pinned comment that addresses an error I made!

In this video we answer the following question: let f(1) = 2021 and for n greater than 1, sum from i=1 to n of f(i) = n^2f(n). Find f(2021).
This question might sound hard at first , but it simplifies into a simple problem.

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