a geometric AM-GM derivation @drpeyam
a geometric AM-GM derivation  @drpeyam
Uploaded April 2023 | Updated September 2026, 1 week ago
a geometric AM-GM derivation. We prove the arithmetic-geometric mean inequality by comparing areas of triangles. This generalizes to higher dimensions with boxes, although I'm not sure of the proof. AM GM says that the geometric mean sqrt ab is always less than or equal to the arithmetic mean a+b/2

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a geometric AM-GM derivationa logarrific differential equationCan you solve this PhD entrance exam number theory question?can you solve this faster than a math prof?what a deranged number!!Norms are equivalentBut WHY does it work? Separation of VariablesIrrational powers?Fresnel Integrala mathematically stunning formulaWhat an odd sum!!infinitely many people failed this interview question
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a geometric AM-GM derivation

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