Uploaded February 2026 | Updated September 2026, 2 weeks ago
Here's a fun calculus proof from the National Taiwan University entrance exam for transfer students. We will show that If f(0)=0 and abs(f'(x)) is less than or equal to abs(f(x)), then f(x)=0 on [0, 1/2]. The key to solving this problem is to apply the Mean Value Theorem and the Extreme Value Theorem. Try the test https://exam.lib.ntu.edu.tw/sites/default/files/exam/undergra/103/18_001-103.pdf
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Here's a fun calculus proof from the National Taiwan University entrance exam for transfer students. We will show that If f(0)=0 and abs(f'(x)) is less than or equal to abs(f(x)), then f(x)=0 on [0, 1/2]. The key to solving this problem is to apply the Mean Value Theorem and the Extreme Value Theorem. Try the test https://exam.lib.ntu.edu.tw/sites/default/files/exam/undergra/103/18_001-103.pdf
π Shop my math t-shirts & hoodies: π amzn.to/3qBeuw6
π Support this channel and get more content patreon.com/blackpenredpen
#blackpenredpen #calculus
