Uploaded August 2015 | Updated September 2026, 3 weeks ago
Music Used:
-Techno Castle: youtu.be/l2i4gNsVWyU
-Above the Clouds: youtu.be/7bk3HyfUQVA
-Lost Night: (No Link available ATM)
Linked videos at the ends:
-How to
-Techno Castle FL: youtu.be/iV79fMfOU4Y
I apologize as there is probably better ways to convert this into percentages and figure of the amount of salt needed but I had never learned how to convert Percentages into Workable Volumes in school so I had came up with this formula as a way for me to personally convert it over. Teachers always Hated me as I always done Math in Unconventional ways, with formula's they didn't quite grasp, yet would still get the right answers :]
But to be honest It's probably not the simplest way to do this, however it's accurate and served me well so far. Or you can skip all of that by just Googling it... For example “What's 30% [Water percentage] of 120oz..? [Total Volume of liquid]” then multiply the results by 10.617 like we do below.
100% - (Isopropanol %) = (Water Content %)
(Total Volume of Liquid {Do this in Ounces}) / 100 = (X)
(Total Volume of Liquid) / (X) = 100 (Not Actually a step but a way to check if you've done this right.)
(Water content %) x (X) = (Water content in ounces)
Then we times it by 10.617 or the Grams of salt soluble in one ounce of water. As 1 liter can dissolve 359g and 1 liter is 33.814 Ounces. So 359 / 33.814 = 10.61690424084699 (10.617 if we round up.)
(Water content in ounces) x 10.617 = (Approximate salt amount we need in Grams)
*For example if we had 17oz of 70% Isopropanol it'd look like this:*
100% - (70%) = (30%)
(17oz) / 100 = (.17)
(17oz) / (.17) = 100
(30) x (.17) = 5.1oz of water
(5.1oz) x 10.617 = 54.1467 grams of salt.
Music Used:
-Techno Castle: youtu.be/l2i4gNsVWyU
-Above the Clouds: youtu.be/7bk3HyfUQVA
-Lost Night: (No Link available ATM)
Linked videos at the ends:
-How to
-Techno Castle FL: youtu.be/iV79fMfOU4Y
I apologize as there is probably better ways to convert this into percentages and figure of the amount of salt needed but I had never learned how to convert Percentages into Workable Volumes in school so I had came up with this formula as a way for me to personally convert it over. Teachers always Hated me as I always done Math in Unconventional ways, with formula's they didn't quite grasp, yet would still get the right answers :]
But to be honest It's probably not the simplest way to do this, however it's accurate and served me well so far. Or you can skip all of that by just Googling it... For example “What's 30% [Water percentage] of 120oz..? [Total Volume of liquid]” then multiply the results by 10.617 like we do below.
100% - (Isopropanol %) = (Water Content %)
(Total Volume of Liquid {Do this in Ounces}) / 100 = (X)
(Total Volume of Liquid) / (X) = 100 (Not Actually a step but a way to check if you've done this right.)
(Water content %) x (X) = (Water content in ounces)
Then we times it by 10.617 or the Grams of salt soluble in one ounce of water. As 1 liter can dissolve 359g and 1 liter is 33.814 Ounces. So 359 / 33.814 = 10.61690424084699 (10.617 if we round up.)
(Water content in ounces) x 10.617 = (Approximate salt amount we need in Grams)
*For example if we had 17oz of 70% Isopropanol it'd look like this:*
100% - (70%) = (30%)
(17oz) / 100 = (.17)
(17oz) / (.17) = 100
(30) x (.17) = 5.1oz of water
(5.1oz) x 10.617 = 54.1467 grams of salt.
